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132002311200979 is a prime number
BaseRepresentation
bin11110000000111000101110…
…110111100110000011010011
3122022101022001000210022110011
4132000320232313212003103
5114300211213131412404
61144425005152015351
736542565220122022
oct3600705667460323
9568338030708404
10132002311200979
113907295841a56a
121297ab22b31557
1358869c28b3aab
142484d359948b9
15103da3a40b604
hex780e2ede60d3

132002311200979 has 2 divisors, whose sum is σ = 132002311200980. Its totient is φ = 132002311200978.

The previous prime is 132002311200961. The next prime is 132002311200997. The reversal of 132002311200979 is 979002113200231.

Together with next prime (132002311200997) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (132002311200961) and next prime (132002311200997).

It is a cyclic number.

It is not a de Polignac number, because 132002311200979 - 29 = 132002311200467 is a prime.

It is a super-2 number, since 2×1320023112009792 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132002311200919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66001155600489 + 66001155600490.

It is an arithmetic number, because the mean of its divisors is an integer number (66001155600490).

Almost surely, 2132002311200979 is an apocalyptic number.

132002311200979 is a deficient number, since it is larger than the sum of its proper divisors (1).

132002311200979 is an equidigital number, since it uses as much as digits as its factorization.

132002311200979 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40824, while the sum is 40.

The spelling of 132002311200979 in words is "one hundred thirty-two trillion, two billion, three hundred eleven million, two hundred thousand, nine hundred seventy-nine".