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13200244234521 = 34400081411507
BaseRepresentation
bin1100000000010110101111…
…0111100101100100011001
31201201221010201100121112220
43000011223313211210121
53212233100011001041
644024035233254253
72531454233455401
oct300055367454431
951657121317486
1013200244234521
11422a212816a03
121592367104389
13749a1577b956
14338c76721801
1517d57e2a1d66
hexc016bde5919

13200244234521 has 4 divisors (see below), whose sum is σ = 17600325646032. Its totient is φ = 8800162823012.

The previous prime is 13200244234519. The next prime is 13200244234549. The reversal of 13200244234521 is 12543244200231.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13200244234521 - 21 = 13200244234519 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13200244234721) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2200040705751 + ... + 2200040705756.

It is an arithmetic number, because the mean of its divisors is an integer number (4400081411508).

Almost surely, 213200244234521 is an apocalyptic number.

It is an amenable number.

13200244234521 is a deficient number, since it is larger than the sum of its proper divisors (4400081411511).

13200244234521 is an equidigital number, since it uses as much as digits as its factorization.

13200244234521 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4400081411510.

The product of its (nonzero) digits is 46080, while the sum is 33.

Adding to 13200244234521 its reverse (12543244200231), we get a palindrome (25743488434752).

The spelling of 13200244234521 in words is "thirteen trillion, two hundred billion, two hundred forty-four million, two hundred thirty-four thousand, five hundred twenty-one".

Divisors: 1 3 4400081411507 13200244234521