Base | Representation |
---|---|
bin | 11110000000111001011001… |
… | …110010001110000001001111 |
3 | 122022101100220012121200001010 |
4 | 132000321121302032001033 |
5 | 114300214201442241421 |
6 | 1144425204432220303 |
7 | 36542622112116603 |
oct | 3600713162160117 |
9 | 568340805550033 |
10 | 132003031212111 |
11 | 39073197897594 |
12 | 1297b0a409a693 |
13 | 5886aa8b0b697 |
14 | 2484da345b503 |
15 | 103da7d733076 |
hex | 780e59c8e04f |
132003031212111 has 4 divisors (see below), whose sum is σ = 176004041616152. Its totient is φ = 88002020808072.
The previous prime is 132003031212109. The next prime is 132003031212119. The reversal of 132003031212111 is 111212130300231.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 132003031212111 - 21 = 132003031212109 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132003031212119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22000505202016 + ... + 22000505202021.
It is an arithmetic number, because the mean of its divisors is an integer number (44001010404038).
Almost surely, 2132003031212111 is an apocalyptic number.
132003031212111 is a deficient number, since it is larger than the sum of its proper divisors (44001010404041).
132003031212111 is an equidigital number, since it uses as much as digits as its factorization.
132003031212111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44001010404040.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 132003031212111 its reverse (111212130300231), we get a palindrome (243215161512342).
The spelling of 132003031212111 in words is "one hundred thirty-two trillion, three billion, thirty-one million, two hundred twelve thousand, one hundred eleven".
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