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132003110420443 = 1121793111767153
BaseRepresentation
bin11110000000111001011110…
…100000010111111111011011
3122022101101002201122212110001
4132000321132200113333123
5114300214332231423233
61144425220342033431
736542624063304643
oct3600713640277733
9568341081585401
10132003110420443
1139073228577a19
121297b106718877
135886abc352612
142484dadb99523
15103da8567c27d
hex780e5e817fdb

132003110420443 has 4 divisors (see below), whose sum is σ = 132003133405528. Its totient is φ = 132003087435360.

The previous prime is 132003110420431. The next prime is 132003110420449. The reversal of 132003110420443 is 344024011300231.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 132003110420443 - 29 = 132003110419931 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132003110420449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5334355 + ... + 17101507.

It is an arithmetic number, because the mean of its divisors is an integer number (33000783351382).

Almost surely, 2132003110420443 is an apocalyptic number.

132003110420443 is a deficient number, since it is larger than the sum of its proper divisors (22985085).

132003110420443 is a wasteful number, since it uses less digits than its factorization.

132003110420443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22985084.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 132003110420443 its reverse (344024011300231), we get a palindrome (476027121720674).

The spelling of 132003110420443 in words is "one hundred thirty-two trillion, three billion, one hundred ten million, four hundred twenty thousand, four hundred forty-three".

Divisors: 1 11217931 11767153 132003110420443