13200311122020 has 288 divisors, whose sum is σ = 44890402677120. Its totient is φ = 3111587758080.

The previous prime is 13200311122007. The next prime is 13200311122021. The reversal of 13200311122020 is 2022111300231.

13200311122020 is a `hidden beast` number, since 1 + 320 + 0 + 31 + 112 + 202 + 0 = 666.

13200311122020 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×13200311122020² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13200311121984 and 13200311122002.

It is not an unprimeable number, because it can be changed into a prime (13200311122021) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 115620484 + ... + 115734596.

It is an arithmetic number, because the mean of its divisors is an integer number (155869453740).

Almost surely, 2^{13200311122020} is an apocalyptic number.

13200311122020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13200311122020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22445201338560).

13200311122020 is an abundant number, since it is smaller than the sum of its proper divisors (31690091555100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13200311122020 is a wasteful number, since it uses less digits than its factorization.

13200311122020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115755 (or 115750 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 13200311122020 its reverse (2022111300231), we get a palindrome (15222422422251).

It can be divided in two parts, 13200311 and 122020, that added together give a palindrome (13322331).

The spelling of 13200311122020 in words is "thirteen trillion, two hundred billion, three hundred eleven million, one hundred twenty-two thousand, twenty".