Base | Representation |
---|---|
bin | 10011001101011000000… |
… | …000101010110111000010 |
3 | 11200012020021012122002202 |
4 | 103031120000222313002 |
5 | 133111411032433214 |
6 | 2450225240513202 |
7 | 164240416606631 |
oct | 23153000526702 |
9 | 4605207178082 |
10 | 1320031530434 |
11 | 469905427521 |
12 | 1939b7a7b802 |
13 | 9762b191826 |
14 | 47c65b1b518 |
15 | 2450c81d6de |
hex | 1335802adc2 |
1320031530434 has 4 divisors (see below), whose sum is σ = 1980047295654. Its totient is φ = 660015765216.
The previous prime is 1320031530409. The next prime is 1320031530439. The reversal of 1320031530434 is 4340351300231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 958646601025 + 361384929409 = 979105^2 + 601153^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1320031530397 and 1320031530406.
It is not an unprimeable number, because it can be changed into a prime (1320031530439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330007882607 + ... + 330007882610.
Almost surely, 21320031530434 is an apocalyptic number.
1320031530434 is a deficient number, since it is larger than the sum of its proper divisors (660015765220).
1320031530434 is an equidigital number, since it uses as much as digits as its factorization.
1320031530434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 660015765219.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 1320031530434 its reverse (4340351300231), we get a palindrome (5660382830665).
The spelling of 1320031530434 in words is "one trillion, three hundred twenty billion, thirty-one million, five hundred thirty thousand, four hundred thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.114 sec. • engine limits •