Base | Representation |
---|---|
bin | 11110000000111001100011… |
… | …111010110000010110000101 |
3 | 122022101101100001112001210110 |
4 | 132000321203322300112011 |
5 | 114300220024003101041 |
6 | 1144425233344143233 |
7 | 36542626245146403 |
oct | 3600714372602605 |
9 | 568341301461713 |
10 | 132003201222021 |
11 | 39073274856548 |
12 | 1297b131007b19 |
13 | 5886b050c536c |
14 | 2484dbbc74473 |
15 | 103da8d616516 |
hex | 780e63eb0585 |
132003201222021 has 16 divisors (see below), whose sum is σ = 176114568337344. Its totient is φ = 87946985833344.
The previous prime is 132003201222001. The next prime is 132003201222023. The reversal of 132003201222021 is 120222102300231.
It is not a de Polignac number, because 132003201222021 - 211 = 132003201219973 is a prime.
It is a super-2 number, since 2×1320032012220212 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132003201222023) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 379677361 + ... + 380024873.
It is an arithmetic number, because the mean of its divisors is an integer number (11007160521084).
Almost surely, 2132003201222021 is an apocalyptic number.
It is an amenable number.
132003201222021 is a deficient number, since it is larger than the sum of its proper divisors (44111367115323).
132003201222021 is a wasteful number, since it uses less digits than its factorization.
132003201222021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 426500.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 132003201222021 its reverse (120222102300231), we get a palindrome (252225303522252).
The spelling of 132003201222021 in words is "one hundred thirty-two trillion, three billion, two hundred one million, two hundred twenty-two thousand, twenty-one".
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