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13200322110103 = 20816343259063
BaseRepresentation
bin1100000000010111000010…
…0000101010001010010111
31201201221100010220002202201
43000011300200222022113
53212233224430010403
644024051054345331
72531456200423042
oct300056040521227
951657303802681
1013200322110103
11422a252776a97
1215923891bb247
13749a2894708b
14338c82bd3c59
1517d58603621d
hexc017082a297

13200322110103 has 4 divisors (see below), whose sum is σ = 13206665371248. Its totient is φ = 13193978848960.

The previous prime is 13200322110071. The next prime is 13200322110133. The reversal of 13200322110103 is 30101122300231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13200322110103 - 25 = 13200322110071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13200322110133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3171627451 + ... + 3171631612.

It is an arithmetic number, because the mean of its divisors is an integer number (3301666342812).

Almost surely, 213200322110103 is an apocalyptic number.

13200322110103 is a deficient number, since it is larger than the sum of its proper divisors (6343261145).

13200322110103 is an equidigital number, since it uses as much as digits as its factorization.

13200322110103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6343261144.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13200322110103 its reverse (30101122300231), we get a palindrome (43301444410334).

The spelling of 13200322110103 in words is "thirteen trillion, two hundred billion, three hundred twenty-two million, one hundred ten thousand, one hundred three".

Divisors: 1 2081 6343259063 13200322110103