13200421301011 has 4 divisors (see below), whose sum is σ = 15086195772592. Its totient is φ = 11314646829432.

The previous prime is 13200421300991. The next prime is 13200421301059. The reversal of 13200421301011 is 11010312400231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13200421301011 - 2³³ = 13191831366419 is a prime.

It is a super-2 number, since 2×13200421301011² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13200421301011.

It is not an unprimeable number, because it can be changed into a prime (13200421901011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 942887235780 + ... + 942887235793.

It is an arithmetic number, because the mean of its divisors is an integer number (3771548943148).

Almost surely, 2^{13200421301011} is an apocalyptic number.

13200421301011 is a deficient number, since it is larger than the sum of its proper divisors (1885774471581).

13200421301011 is an equidigital number, since it uses as much as digits as its factorization.

13200421301011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1885774471580.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13200421301011 its reverse (11010312400231), we get a palindrome (24210733701242).

The spelling of 13200421301011 in words is "thirteen trillion, two hundred billion, four hundred twenty-one million, three hundred one thousand, eleven".