Base | Representation |
---|---|
bin | 1100000000010111011001… |
… | …1011000010101011111111 |
3 | 1201201221121001112112002022 |
4 | 3000011312123002223333 |
5 | 3212233430323112431 |
6 | 44024105000350355 |
7 | 2531461513505231 |
oct | 300056633025377 |
9 | 51657531475068 |
10 | 13200421300991 |
11 | 422a2a3765631 |
12 | 15923b64753bb |
13 | 749a43366502 |
14 | 338c92054251 |
15 | 17d58eacb07b |
hex | c01766c2aff |
13200421300991 has 2 divisors, whose sum is σ = 13200421300992. Its totient is φ = 13200421300990.
The previous prime is 13200421300973. The next prime is 13200421301059. The reversal of 13200421300991 is 19900312400231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13200421300991 - 238 = 12925543394047 is a prime.
It is a super-2 number, since 2×132004213009912 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13200421300951) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600210650495 + 6600210650496.
It is an arithmetic number, because the mean of its divisors is an integer number (6600210650496).
Almost surely, 213200421300991 is an apocalyptic number.
13200421300991 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200421300991 is an equidigital number, since it uses as much as digits as its factorization.
13200421300991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664, while the sum is 35.
The spelling of 13200421300991 in words is "thirteen trillion, two hundred billion, four hundred twenty-one million, three hundred thousand, nine hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •