Base | Representation |
---|---|
bin | 111101011110000010… |
… | …0111001100110111111 |
3 | 110121201121121022222202 |
4 | 1322330010321212333 |
5 | 4130321112420111 |
6 | 140350400502115 |
7 | 12352123025351 |
oct | 1727404714677 |
9 | 417647538882 |
10 | 132004420031 |
11 | 50a8a065610 |
12 | 2170001a93b |
13 | c5a92389a3 |
14 | 65637950d1 |
15 | 3678ceab3b |
hex | 1ebc1399bf |
132004420031 has 8 divisors (see below), whose sum is σ = 144020771328. Its totient is φ = 119990727000.
The previous prime is 132004420003. The next prime is 132004420057. The reversal of 132004420031 is 130024400231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132004420031 - 210 = 132004419007 is a prime.
It is a super-2 number, since 2×1320044200312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132004419985 and 132004420012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132004420531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 560015 + ... + 760016.
It is an arithmetic number, because the mean of its divisors is an integer number (18002596416).
Almost surely, 2132004420031 is an apocalyptic number.
132004420031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
132004420031 is a deficient number, since it is larger than the sum of its proper divisors (12016351297).
132004420031 is a wasteful number, since it uses less digits than its factorization.
132004420031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1329133.
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 132004420031 its reverse (130024400231), we get a palindrome (262028820262).
The spelling of 132004420031 in words is "one hundred thirty-two billion, four million, four hundred twenty thousand, thirty-one".
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