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132005123450035 = 51118919126861523
BaseRepresentation
bin11110000000111011010110…
…011111011110010010110011
3122022101120022000112100220121
4132000323112133132102303
5114300232443100400120
61144430152212151111
736543025005624613
oct3600732637362263
9568346260470817
10132005123450035
1139074070903940
121297b588908497
13588705040c4a4
142485121286a43
15103db522655aa
hex780ed67de4b3

132005123450035 has 16 divisors (see below), whose sum is σ = 172815842453760. Its totient is φ = 95998650927840.

The previous prime is 132005123450021. The next prime is 132005123450093. The reversal of 132005123450035 is 530054321500231.

It is not a de Polignac number, because 132005123450035 - 25 = 132005123450003 is a prime.

It is a super-2 number, since 2×1320051234500352 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62390217 + ... + 64471306.

It is an arithmetic number, because the mean of its divisors is an integer number (10800990153360).

Almost surely, 2132005123450035 is an apocalyptic number.

132005123450035 is a deficient number, since it is larger than the sum of its proper divisors (40810719003725).

132005123450035 is a wasteful number, since it uses less digits than its factorization.

132005123450035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 126880458.

The product of its (nonzero) digits is 54000, while the sum is 34.

Adding to 132005123450035 its reverse (530054321500231), we get a palindrome (662059444950266).

The spelling of 132005123450035 in words is "one hundred thirty-two trillion, five billion, one hundred twenty-three million, four hundred fifty thousand, thirty-five".

Divisors: 1 5 11 55 18919 94595 208109 1040545 126861523 634307615 1395476753 6977383765 2400093153637 12000465768185 26401024690007 132005123450035