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132010433114 = 279429316651
BaseRepresentation
bin111101011110001101…
…1110101101001011010
3110121202000220211101112
41322330123311221122
54130324132324424
6140351133420322
712352225111250
oct1727433655132
9417660824345
10132010433114
1150a924a22aa
122170203a6a2
13c5aa562921
1465644bc5d0
1536795d760e
hex1ebc6f5a5a

132010433114 has 8 divisors (see below), whose sum is σ = 226303599648. Its totient is φ = 56575899900.

The previous prime is 132010433069. The next prime is 132010433131. The reversal of 132010433114 is 411334010231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a self number, because there is not a number n which added to its sum of digits gives 132010433114.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4714658312 + ... + 4714658339.

It is an arithmetic number, because the mean of its divisors is an integer number (28287949956).

Almost surely, 2132010433114 is an apocalyptic number.

132010433114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

132010433114 is a deficient number, since it is larger than the sum of its proper divisors (94293166534).

132010433114 is an equidigital number, since it uses as much as digits as its factorization.

132010433114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9429316660.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 132010433114 its reverse (411334010231), we get a palindrome (543344443345).

The spelling of 132010433114 in words is "one hundred thirty-two billion, ten million, four hundred thirty-three thousand, one hundred fourteen".

Divisors: 1 2 7 14 9429316651 18858633302 66005216557 132010433114