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132011023 = 463285121
BaseRepresentation
bin1111101111001…
…01010000001111
3100012101212002011
413313211100033
5232243323043
621033242051
73162034534
oct767452017
9305355064
10132011023
1168575921
1238263327
1321470c41
1413764d8b
15b8c959d
hex7de540f

132011023 has 4 divisors (see below), whose sum is σ = 132296608. Its totient is φ = 131725440.

The previous prime is 132011003. The next prime is 132011027. The reversal of 132011023 is 320110231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132011023 - 29 = 132010511 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132010994 and 132011012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132011027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142098 + ... + 143023.

It is an arithmetic number, because the mean of its divisors is an integer number (33074152).

Almost surely, 2132011023 is an apocalyptic number.

132011023 is a deficient number, since it is larger than the sum of its proper divisors (285585).

132011023 is an equidigital number, since it uses as much as digits as its factorization.

132011023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 285584.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 132011023 is about 11489.6049975619. The cubic root of 132011023 is about 509.1785095979.

Adding to 132011023 its reverse (320110231), we get a palindrome (452121254).

The spelling of 132011023 in words is "one hundred thirty-two million, eleven thousand, twenty-three".

Divisors: 1 463 285121 132011023