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132011350020 = 223351149145263
BaseRepresentation
bin111101011110001111…
…1010101100000000100
3110121202002122102011000
41322330133111200010
54130324401200040
6140351205213300
712352235650404
oct1727437254004
9417662572130
10132011350020
1150a92a69180
1221702401230
13c5aa7c4084
14656467a804
153679719130
hex1ebc7d5804

132011350020 has 192 divisors, whose sum is σ = 448960942080. Its totient is φ = 31936867200.

The previous prime is 132011350007. The next prime is 132011350049. The reversal of 132011350020 is 20053110231.

132011350020 is a `hidden beast` number, since 1 + 32 + 0 + 113 + 500 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 132011349975 and 132011350002.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2893909 + ... + 2939171.

It is an arithmetic number, because the mean of its divisors is an integer number (2338338240).

Almost surely, 2132011350020 is an apocalyptic number.

132011350020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132011350020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (224480471040).

132011350020 is an abundant number, since it is smaller than the sum of its proper divisors (316949592060).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132011350020 is a wasteful number, since it uses less digits than its factorization.

132011350020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45783 (or 45775 counting only the distinct ones).

The product of its (nonzero) digits is 180, while the sum is 18.

Adding to 132011350020 its reverse (20053110231), we get a palindrome (152064460251).

The spelling of 132011350020 in words is "one hundred thirty-two billion, eleven million, three hundred fifty thousand, twenty".