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13201240234551 = 3197919001117023
BaseRepresentation
bin1100000000011010011100…
…1111000001101000110111
31201202000201010111122201220
43000012213033001220313
53212242120000001201
644024322133121423
72531521016356515
oct300064717015067
951660633448656
1013201240234551
11422a683a58526
1215925a4789273
13749b43c18295
14338d2cb0b4b5
1517d5db943036
hexc01a73c1a37

13201240234551 has 16 divisors (see below), whose sum is σ = 17611625180160. Its totient is φ = 8795841608000.

The previous prime is 13201240234543. The next prime is 13201240234603. The reversal of 13201240234551 is 15543204210231.

It is a cyclic number.

It is not a de Polignac number, because 13201240234551 - 23 = 13201240234543 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13201240234541) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 112750426 + ... + 112867448.

It is an arithmetic number, because the mean of its divisors is an integer number (1100726573760).

Almost surely, 213201240234551 is an apocalyptic number.

13201240234551 is a deficient number, since it is larger than the sum of its proper divisors (4410384945609).

13201240234551 is a wasteful number, since it uses less digits than its factorization.

13201240234551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 138006.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 13201240234551 its reverse (15543204210231), we get a palindrome (28744444444782).

The spelling of 13201240234551 in words is "thirteen trillion, two hundred one billion, two hundred forty million, two hundred thirty-four thousand, five hundred fifty-one".

Divisors: 1 3 1979 5937 19001 57003 117023 351069 37602979 112808937 231588517 694765551 2223554023 6670662069 4400413411517 13201240234551