Base | Representation |
---|---|
bin | 10011001101011101100… |
… | …001101010001110001101 |
3 | 11200012110201022212012001 |
4 | 103031131201222032031 |
5 | 133112103230032103 |
6 | 2450242344112301 |
7 | 164242622255662 |
oct | 23153541521615 |
9 | 4605421285161 |
10 | 1320124064653 |
11 | 469952689889 |
12 | 193a22a65691 |
13 | 976443c00c4 |
14 | 47c74127a69 |
15 | 245159eb01d |
hex | 1335d86a38d |
1320124064653 has 4 divisors (see below), whose sum is σ = 1320157884640. Its totient is φ = 1320090244668.
The previous prime is 1320124064627. The next prime is 1320124064663. The reversal of 1320124064653 is 3564604210231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320124064653 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1320124064663) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16851375 + ... + 16929532.
It is an arithmetic number, because the mean of its divisors is an integer number (330039471160).
Almost surely, 21320124064653 is an apocalyptic number.
It is an amenable number.
1320124064653 is a deficient number, since it is larger than the sum of its proper divisors (33819987).
1320124064653 is an equidigital number, since it uses as much as digits as its factorization.
1320124064653 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33819986.
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 1320124064653 its reverse (3564604210231), we get a palindrome (4884728274884).
The spelling of 1320124064653 in words is "one trillion, three hundred twenty billion, one hundred twenty-four million, sixty-four thousand, six hundred fifty-three".
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