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132013113120 = 2535573115647
BaseRepresentation
bin111101011110010011…
…0000011111100100000
3110121202012221222200000
41322330212003330200
54130330324104440
6140351311100000
712352256642550
oct1727446037440
9417665858600
10132013113120
1150a93a62889
1221702b11600
13c5aac90725
1465649b9160
153679966730
hex1ebc983f20

132013113120 has 576 divisors, whose sum is σ = 551178141696. Its totient is φ = 29199191040.

The previous prime is 132013113103. The next prime is 132013113121. The reversal of 132013113120 is 21311310231.

132013113120 is a `hidden beast` number, since 1 + 320 + 1 + 31 + 1 + 312 + 0 = 666.

It is a super-2 number, since 2×1320131131202 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 132013113093 and 132013113102.

It is not an unprimeable number, because it can be changed into a prime (132013113121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 8429137 + ... + 8444783.

It is an arithmetic number, because the mean of its divisors is an integer number (956906496).

Almost surely, 2132013113120 is an apocalyptic number.

132013113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132013113120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (275589070848).

132013113120 is an abundant number, since it is smaller than the sum of its proper divisors (419165028576).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132013113120 is a wasteful number, since it uses less digits than its factorization.

132013113120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15715 (or 15695 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 132013113120 its reverse (21311310231), we get a palindrome (153324423351).

The spelling of 132013113120 in words is "one hundred thirty-two billion, thirteen million, one hundred thirteen thousand, one hundred twenty".