1320133121233 has 4 divisors (see below), whose sum is σ = 1323283797360. Its totient is φ = 1316982445108.

The previous prime is 1320133121231. The next prime is 1320133121261. The reversal of 1320133121233 is 3321213310231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1320133121233 - 2¹ = 1320133121231 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1320133121198 and 1320133121207.

It is not an unprimeable number, because it can be changed into a prime (1320133121231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1575337435 + ... + 1575338272.

It is an arithmetic number, because the mean of its divisors is an integer number (330820949340).

Almost surely, 2^{1320133121233} is an apocalyptic number.

It is an amenable number.

1320133121233 is a deficient number, since it is larger than the sum of its proper divisors (3150676127).

1320133121233 is an equidigital number, since it uses as much as digits as its factorization.

1320133121233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3150676126.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1320133121233 its reverse (3321213310231), we get a palindrome (4641346431464).

The spelling of 1320133121233 in words is "one trillion, three hundred twenty billion, one hundred thirty-three million, one hundred twenty-one thousand, two hundred thirty-three".