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132013335 = 358800889
BaseRepresentation
bin1111101111001…
…01110100010111
3100012101222020210
413313211310113
5232243411320
621033300503
73162044346
oct767456427
9305358223
10132013335
1168577633
1238264733
1321471ccc
1413765b5d
15b8ca0e0
hex7de5d17

132013335 has 8 divisors (see below), whose sum is σ = 211221360. Its totient is φ = 70407104.

The previous prime is 132013331. The next prime is 132013369. The reversal of 132013335 is 533310231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132013335 - 22 = 132013331 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132013331) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4400430 + ... + 4400459.

It is an arithmetic number, because the mean of its divisors is an integer number (26402670).

Almost surely, 2132013335 is an apocalyptic number.

132013335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

132013335 is a deficient number, since it is larger than the sum of its proper divisors (79208025).

132013335 is an equidigital number, since it uses as much as digits as its factorization.

132013335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8800897.

The product of its (nonzero) digits is 810, while the sum is 21.

The square root of 132013335 is about 11489.7056098057. The cubic root of 132013335 is about 509.1814821119.

Adding to 132013335 its reverse (533310231), we get a palindrome (665323566).

The spelling of 132013335 in words is "one hundred thirty-two million, thirteen thousand, three hundred thirty-five".

Divisors: 1 3 5 15 8800889 26402667 44004445 132013335