Base | Representation |
---|---|
bin | 1111101111001… |
… | …01110101101101 |
3 | 100012101222100222 |
4 | 13313211311231 |
5 | 232243412141 |
6 | 21033301125 |
7 | 3162044531 |
oct | 767456555 |
9 | 305358328 |
10 | 132013421 |
11 | 68577701 |
12 | 382647a5 |
13 | 21472067 |
14 | 13765bc1 |
15 | b8ca14b |
hex | 7de5d6d |
132013421 has 4 divisors (see below), whose sum is σ = 132039072. Its totient is φ = 131987772.
The previous prime is 132013417. The next prime is 132013457. The reversal of 132013421 is 124310231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 124310231 = 293 ⋅424267.
It is a cyclic number.
It is not a de Polignac number, because 132013421 - 22 = 132013417 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 132013421.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132013471) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2135 + ... + 16388.
It is an arithmetic number, because the mean of its divisors is an integer number (33009768).
Almost surely, 2132013421 is an apocalyptic number.
It is an amenable number.
132013421 is a deficient number, since it is larger than the sum of its proper divisors (25651).
132013421 is an equidigital number, since it uses as much as digits as its factorization.
132013421 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25650.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 132013421 is about 11489.7093522856. The cubic root of 132013421 is about 509.1815926806.
Adding to 132013421 its reverse (124310231), we get a palindrome (256323652).
It can be divided in two parts, 1320 and 13421, that added together give a palindrome (14741).
The spelling of 132013421 in words is "one hundred thirty-two million, thirteen thousand, four hundred twenty-one".
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