13201351440301 has 4 divisors (see below), whose sum is σ = 13201645823104. Its totient is φ = 13201057057500.

The previous prime is 13201351440287. The next prime is 13201351440341. The reversal of 13201351440301 is 10304415310231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13201351440301 - 2⁵ = 13201351440269 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13201351440301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13201351440341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147124125 + ... + 147213826.

It is an arithmetic number, because the mean of its divisors is an integer number (3300411455776).

Almost surely, 2^{13201351440301} is an apocalyptic number.

It is an amenable number.

13201351440301 is a deficient number, since it is larger than the sum of its proper divisors (294382803).

13201351440301 is an equidigital number, since it uses as much as digits as its factorization.

13201351440301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 294382802.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 13201351440301 its reverse (10304415310231), we get a palindrome (23505766750532).

The spelling of 13201351440301 in words is "thirteen trillion, two hundred one billion, three hundred fifty-one million, four hundred forty thousand, three hundred one".