Base | Representation |
---|---|
bin | 11110000001000011001011… |
… | …111000010101111010000101 |
3 | 122022102101000021000101111212 |
4 | 132001003023320111322011 |
5 | 114300402210022321001 |
6 | 1144434103024341205 |
7 | 36543443320630463 |
oct | 3601031370257205 |
9 | 568371007011455 |
10 | 132013535354501 |
11 | 390776981381a9 |
12 | 12981135a74805 |
13 | 5887a910a1558 |
14 | 24856bc533833 |
15 | 103de959c67bb |
hex | 7810cbe15e85 |
132013535354501 has 4 divisors (see below), whose sum is σ = 133295220163872. Its totient is φ = 130731850545132.
The previous prime is 132013535354447. The next prime is 132013535354531. The reversal of 132013535354501 is 105453535310231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132013535354501 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132013535354531) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 640842404531 + ... + 640842404736.
It is an arithmetic number, because the mean of its divisors is an integer number (33323805040968).
Almost surely, 2132013535354501 is an apocalyptic number.
It is an amenable number.
132013535354501 is a deficient number, since it is larger than the sum of its proper divisors (1281684809371).
132013535354501 is a wasteful number, since it uses less digits than its factorization.
132013535354501 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1281684809370.
The product of its (nonzero) digits is 405000, while the sum is 41.
The spelling of 132013535354501 in words is "one hundred thirty-two trillion, thirteen billion, five hundred thirty-five million, three hundred fifty-four thousand, five hundred one".
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