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13201414223001 = 34400471407667
BaseRepresentation
bin1100000000011011000110…
…0110101111010010011001
31201202001011020220012000120
43000012301212233102121
53212242444020114001
644024351310223453
72531525231266464
oct300066146572231
951661136805016
1013201414223001
11422a763194634
121592632ab4b89
13749b70c95b24
14338d47c7c2db
1517d5ebd60236
hexc01b19af499

13201414223001 has 4 divisors (see below), whose sum is σ = 17601885630672. Its totient is φ = 8800942815332.

The previous prime is 13201414222933. The next prime is 13201414223009. The reversal of 13201414223001 is 10032241410231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13201414223001 - 29 = 13201414222489 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13201414223009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2200235703831 + ... + 2200235703836.

It is an arithmetic number, because the mean of its divisors is an integer number (4400471407668).

Almost surely, 213201414223001 is an apocalyptic number.

It is an amenable number.

13201414223001 is a deficient number, since it is larger than the sum of its proper divisors (4400471407671).

13201414223001 is an equidigital number, since it uses as much as digits as its factorization.

13201414223001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4400471407670.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 13201414223001 its reverse (10032241410231), we get a palindrome (23233655633232).

The spelling of 13201414223001 in words is "thirteen trillion, two hundred one billion, four hundred fourteen million, two hundred twenty-three thousand, one".

Divisors: 1 3 4400471407667 13201414223001