Base | Representation |
---|---|
bin | 111101011110010101… |
… | …0111111001000100011 |
3 | 110121202022101120121020 |
4 | 1322330222333020203 |
5 | 4130331141413011 |
6 | 140351354500523 |
7 | 12352303630461 |
oct | 1727452771043 |
9 | 417668346536 |
10 | 132014404131 |
11 | 50a94764835 |
12 | 21703434743 |
13 | c5ab32323c |
14 | 6564c33831 |
15 | 3679b1e006 |
hex | 1ebcabf223 |
132014404131 has 4 divisors (see below), whose sum is σ = 176019205512. Its totient is φ = 88009602752.
The previous prime is 132014404121. The next prime is 132014404139. The reversal of 132014404131 is 131404410231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132014404131 - 210 = 132014403107 is a prime.
It is a super-2 number, since 2×1320144041312 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (132014404139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22002400686 + ... + 22002400691.
It is an arithmetic number, because the mean of its divisors is an integer number (44004801378).
Almost surely, 2132014404131 is an apocalyptic number.
132014404131 is a deficient number, since it is larger than the sum of its proper divisors (44004801381).
132014404131 is an equidigital number, since it uses as much as digits as its factorization.
132014404131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44004801380.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 132014404131 its reverse (131404410231), we get a palindrome (263418814362).
The spelling of 132014404131 in words is "one hundred thirty-two billion, fourteen million, four hundred four thousand, one hundred thirty-one".
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