Base | Representation |
---|---|
bin | 1100000000011011011011… |
… | …0011000100101011110011 |
3 | 1201202001101022211022102212 |
4 | 3000012312303010223303 |
5 | 3212243133320424301 |
6 | 44024404101402335 |
7 | 2531530336634162 |
oct | 300066663045363 |
9 | 51661338738385 |
10 | 13201501342451 |
11 | 422a7a8388784 |
12 | 15926581093ab |
13 | 749b860498b6 |
14 | 338d556793d9 |
15 | 17d60481d4bb |
hex | c01b6cc4af3 |
13201501342451 has 8 divisors (see below), whose sum is σ = 14500504907520. Its totient is φ = 11962916547912.
The previous prime is 13201501342411. The next prime is 13201501342459. The reversal of 13201501342451 is 15424310510231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13201501342451 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13201501342459) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15104692175 + ... + 15104693048.
It is an arithmetic number, because the mean of its divisors is an integer number (1812563113440).
Almost surely, 213201501342451 is an apocalyptic number.
13201501342451 is a deficient number, since it is larger than the sum of its proper divisors (1299003565069).
13201501342451 is a wasteful number, since it uses less digits than its factorization.
13201501342451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30209385265.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 13201501342451 its reverse (15424310510231), we get a palindrome (28625811852682).
The spelling of 13201501342451 in words is "thirteen trillion, two hundred one billion, five hundred one million, three hundred forty-two thousand, four hundred fifty-one".
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