132015013433221 has 4 divisors (see below), whose sum is σ = 135582986769292. Its totient is φ = 128447040097152.

The previous prime is 132015013433189. The next prime is 132015013433267. The reversal of 132015013433221 is 122334310510231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 49796817302596 + 82218196130625 = 7056686^2 + 9067425^2 .

It is a cyclic number.

It is not a de Polignac number, because 132015013433221 - 2⁵ = 132015013433189 is a prime.

It is a super-3 number, since 3×132015013433221³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132015013431221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1783986667980 + ... + 1783986668053.

It is an arithmetic number, because the mean of its divisors is an integer number (33895746692323).

Almost surely, 2^{132015013433221} is an apocalyptic number.

It is an amenable number.

132015013433221 is a deficient number, since it is larger than the sum of its proper divisors (3567973336071).

132015013433221 is an equidigital number, since it uses as much as digits as its factorization.

132015013433221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3567973336070.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 132015013433221 its reverse (122334310510231), we get a palindrome (254349323943452).

The spelling of 132015013433221 in words is "one hundred thirty-two trillion, fifteen billion, thirteen million, four hundred thirty-three thousand, two hundred twenty-one".