132015045025111 has 4 divisors (see below), whose sum is σ = 132239942887752. Its totient is φ = 131790147162472.

The previous prime is 132015045025057. The next prime is 132015045025133. The reversal of 132015045025111 is 111520540510231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132015045025111 - 2⁷ = 132015045024983 is a prime.

It is a super-2 number, since 2×132015045025111² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132015045925111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 112448930440 + ... + 112448931613.

It is an arithmetic number, because the mean of its divisors is an integer number (33059985721938).

Almost surely, 2^{132015045025111} is an apocalyptic number.

132015045025111 is a deficient number, since it is larger than the sum of its proper divisors (224897862641).

132015045025111 is an equidigital number, since it uses as much as digits as its factorization.

132015045025111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 224897862640.

The product of its (nonzero) digits is 6000, while the sum is 31.

Adding to 132015045025111 its reverse (111520540510231), we get a palindrome (243535585535342).

The spelling of 132015045025111 in words is "one hundred thirty-two trillion, fifteen billion, forty-five million, twenty-five thousand, one hundred eleven".