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132015540323344 = 2417293477127813
BaseRepresentation
bin11110000001000101000011…
…011000101100010000010000
3122022102120011222201100201011
4132001011003120230100100
5114300420311310321334
61144435034010020304
736543544104605626
oct3601050330542020
9568376158640634
10132015540323344
1139078526968a47
12129815b5417694
135888020598452
14248582c923516
15103e061a1b564
hex78114362c410

132015540323344 has 20 divisors (see below), whose sum is σ = 255794900874796. Its totient is φ = 66003953000832.

The previous prime is 132015540323269. The next prime is 132015540323353. The reversal of 132015540323344 is 443323045510231.

It can be written as a sum of positive squares in 2 ways, for example, as 71903616160000 + 60111924163344 = 8479600^2 + 7753188^2 .

It is a junction number, because it is equal to n+sod(n) for n = 132015540323297 and 132015540323306.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 238287219 + ... + 238840594.

Almost surely, 2132015540323344 is an apocalyptic number.

It is an amenable number.

132015540323344 is a deficient number, since it is larger than the sum of its proper divisors (123779360551452).

132015540323344 is a wasteful number, since it uses less digits than its factorization.

132015540323344 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 477145114 (or 477145108 counting only the distinct ones).

The product of its (nonzero) digits is 518400, while the sum is 40.

Adding to 132015540323344 its reverse (443323045510231), we get a palindrome (575338585833575).

The spelling of 132015540323344 in words is "one hundred thirty-two trillion, fifteen billion, five hundred forty million, three hundred twenty-three thousand, three hundred forty-four".

Divisors: 1 2 4 8 16 17293 34586 69172 138344 276688 477127813 954255626 1908511252 3817022504 7634045008 8250971270209 16501942540418 33003885080836 66007770161672 132015540323344