1320200000323 has 4 divisors (see below), whose sum is σ = 1348289362080. Its totient is φ = 1292110638568.

The previous prime is 1320200000297. The next prime is 1320200000351. The reversal of 1320200000323 is 3230000020231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1320200000323 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1320200000297 and 1320200000306.

It is not an unprimeable number, because it can be changed into a prime (1320200000423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14044680808 + ... + 14044680901.

It is an arithmetic number, because the mean of its divisors is an integer number (337072340520).

Almost surely, 2^{1320200000323} is an apocalyptic number.

1320200000323 is a deficient number, since it is larger than the sum of its proper divisors (28089361757).

1320200000323 is an equidigital number, since it uses as much as digits as its factorization.

1320200000323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28089361756.

The product of its (nonzero) digits is 216, while the sum is 16.

Adding to 1320200000323 its reverse (3230000020231), we get a palindrome (4550200020554).

The spelling of 1320200000323 in words is "one trillion, three hundred twenty billion, two hundred million, three hundred twenty-three", and thus it is an aban number.