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132020131223 = 1013313028731
BaseRepresentation
bin111101011110100000…
…0110101010110010111
3110121202201011112200202
41322331000311112113
54130334123144343
6140352121331115
712352403412521
oct1727500652627
9417681145622
10132020131223
1150a97a16672
1221705336a9b
13c5ac579c56
1465658c4a11
15367a3a0db8
hex1ebd035597

132020131223 has 4 divisors (see below), whose sum is σ = 132033170088. Its totient is φ = 132007092360.

The previous prime is 132020131129. The next prime is 132020131279. The reversal of 132020131223 is 322131020231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132020131223 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132020131195 and 132020131204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132023131223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6504233 + ... + 6524498.

It is an arithmetic number, because the mean of its divisors is an integer number (33008292522).

Almost surely, 2132020131223 is an apocalyptic number.

132020131223 is a deficient number, since it is larger than the sum of its proper divisors (13038865).

132020131223 is a wasteful number, since it uses less digits than its factorization.

132020131223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13038864.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 132020131223 its reverse (322131020231), we get a palindrome (454151151454).

The spelling of 132020131223 in words is "one hundred thirty-two billion, twenty million, one hundred thirty-one thousand, two hundred twenty-three".

Divisors: 1 10133 13028731 132020131223