132020135354453 has 4 divisors (see below), whose sum is σ = 132240536248800. Its totient is φ = 131799734460108.

The previous prime is 132020135354441. The next prime is 132020135354461. The reversal of 132020135354453 is 354453531020231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132020135354453 - 2³⁶ = 131951415877717 is a prime.

It is a super-2 number, since 2×132020135354453² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 132020135354453.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132020135354423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110200446275 + ... + 110200447472.

It is an arithmetic number, because the mean of its divisors is an integer number (33060134062200).

Almost surely, 2^{132020135354453} is an apocalyptic number.

It is an amenable number.

132020135354453 is a deficient number, since it is larger than the sum of its proper divisors (220400894347).

132020135354453 is an equidigital number, since it uses as much as digits as its factorization.

132020135354453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 220400894346.

The product of its (nonzero) digits is 648000, while the sum is 41.

Adding to 132020135354453 its reverse (354453531020231), we get a palindrome (486473666374684).

The spelling of 132020135354453 in words is "one hundred thirty-two trillion, twenty billion, one hundred thirty-five million, three hundred fifty-four thousand, four hundred fifty-three".