Base | Representation |
---|---|
bin | 11110000001001001011010… |
… | …000010010111100000001001 |
3 | 122022110000020210112111212120 |
4 | 132001021122002113200021 |
5 | 114301004400110030231 |
6 | 1144441125531201453 |
7 | 36544101002433366 |
oct | 3601113202274011 |
9 | 568400223474776 |
10 | 132020215314441 |
11 | 3907a50586aa53 |
12 | 1298249aba6289 |
13 | 58885b6cb0c7c |
14 | 2485b5378146d |
15 | 103e237173d96 |
hex | 78125a097809 |
132020215314441 has 32 divisors (see below), whose sum is σ = 177952167773952. Its totient is φ = 87052991155200.
The previous prime is 132020215314409. The next prime is 132020215314451. The reversal of 132020215314441 is 144413512020231.
It is not a de Polignac number, because 132020215314441 - 25 = 132020215314409 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132020215314451) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1340897371 + ... + 1340995823.
It is an arithmetic number, because the mean of its divisors is an integer number (5561005242936).
Almost surely, 2132020215314441 is an apocalyptic number.
It is an amenable number.
132020215314441 is a deficient number, since it is larger than the sum of its proper divisors (45931952459511).
132020215314441 is a wasteful number, since it uses less digits than its factorization.
132020215314441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103793.
The product of its (nonzero) digits is 23040, while the sum is 33.
Adding to 132020215314441 its reverse (144413512020231), we get a palindrome (276433727334672).
The spelling of 132020215314441 in words is "one hundred thirty-two trillion, twenty billion, two hundred fifteen million, three hundred fourteen thousand, four hundred forty-one".
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