1320204423431 has 4 divisors (see below), whose sum is σ = 1320212273352. Its totient is φ = 1320196573512.

The previous prime is 1320204423407. The next prime is 1320204423451. The reversal of 1320204423431 is 1343244020231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1320204423431 is a prime.

It is a super-2 number, since 2×1320204423431² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1320204423394 and 1320204423403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320204423401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3667040 + ... + 4010933.

It is an arithmetic number, because the mean of its divisors is an integer number (330053068338).

Almost surely, 2^{1320204423431} is an apocalyptic number.

1320204423431 is a deficient number, since it is larger than the sum of its proper divisors (7849921).

1320204423431 is an equidigital number, since it uses as much as digits as its factorization.

1320204423431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7849920.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 1320204423431 its reverse (1343244020231), we get a palindrome (2663448443662).

The spelling of 1320204423431 in words is "one trillion, three hundred twenty billion, two hundred four million, four hundred twenty-three thousand, four hundred thirty-one".