1320204431021 has 4 divisors (see below), whose sum is σ = 1508805064032. Its totient is φ = 1131603798012.

The previous prime is 1320204431017. The next prime is 1320204431053. The reversal of 1320204431021 is 1201344020231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1320204431021 - 2² = 1320204431017 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320204431011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94300316495 + ... + 94300316508.

It is an arithmetic number, because the mean of its divisors is an integer number (377201266008).

Almost surely, 2^{1320204431021} is an apocalyptic number.

It is an amenable number.

1320204431021 is a deficient number, since it is larger than the sum of its proper divisors (188600633011).

1320204431021 is an equidigital number, since it uses as much as digits as its factorization.

1320204431021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 188600633010.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1320204431021 its reverse (1201344020231), we get a palindrome (2521548451252).

The spelling of 1320204431021 in words is "one trillion, three hundred twenty billion, two hundred four million, four hundred thirty-one thousand, twenty-one".