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132020533220000 = 255429225131271
BaseRepresentation
bin11110000001001001101100…
…111111000101001010100000
3122022110001001221201210022112
4132001021230333011022200
5114301011023001020000
61144441221245054452
736544111612536635
oct3601115477051240
9568401057653275
10132020533220000
113907a659264117
1212982569557428
135888637b0aa79
142485b83a9618c
15103e25501d235
hex78126cfc52a0

132020533220000 has 360 divisors, whose sum is σ = 337727120002272. Its totient is φ = 50782480000000.

The previous prime is 132020533219943. The next prime is 132020533220071. The reversal of 132020533220000 is 22335020231.

It is an unprimeable number.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 4221804365 + ... + 4221835635.

Almost surely, 2132020533220000 is an apocalyptic number.

132020533220000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132020533220000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (168863560001136).

132020533220000 is an abundant number, since it is smaller than the sum of its proper divisors (205706586782272).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132020533220000 is an equidigital number, since it uses as much as digits as its factorization.

132020533220000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31610 (or 31558 counting only the distinct ones).

The product of its (nonzero) digits is 2160, while the sum is 23.

Adding to 132020533220000 its reverse (22335020231), we get a palindrome (132042868240231).

The spelling of 132020533220000 in words is "one hundred thirty-two trillion, twenty billion, five hundred thirty-three million, two hundred twenty thousand".