Base | Representation |
---|---|
bin | 11110000001001001101101… |
… | …011101111010000100110101 |
3 | 122022110001002111221100102111 |
4 | 132001021231131322010311 |
5 | 114301011032033113140 |
6 | 1144441222134211021 |
7 | 36544112041324555 |
oct | 3601115535720465 |
9 | 568401074840374 |
10 | 132020541301045 |
11 | 3907a662883571 |
12 | 129825701b3a71 |
13 | 58886396aa057 |
14 | 2485b84b9b165 |
15 | 103e255ab77ea |
hex | 78126d77a135 |
132020541301045 has 16 divisors (see below), whose sum is σ = 159234337658880. Its totient is φ = 105076678028224.
The previous prime is 132020541301013. The next prime is 132020541301109. The reversal of 132020541301045 is 540103145020231.
It is a cyclic number.
It is not a de Polignac number, because 132020541301045 - 25 = 132020541301013 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132020541300998 and 132020541301016.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26385036 + ... + 30987274.
It is an arithmetic number, because the mean of its divisors is an integer number (9952146103680).
Almost surely, 2132020541301045 is an apocalyptic number.
It is an amenable number.
132020541301045 is a deficient number, since it is larger than the sum of its proper divisors (27213796357835).
132020541301045 is a wasteful number, since it uses less digits than its factorization.
132020541301045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4631564.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 132020541301045 its reverse (540103145020231), we get a palindrome (672123686321276).
The spelling of 132020541301045 in words is "one hundred thirty-two trillion, twenty billion, five hundred forty-one million, three hundred one thousand, forty-five".
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