Base | Representation |
---|---|
bin | 11110000001001010010101… |
… | …011001000100110110101001 |
3 | 122022110002211012022211120020 |
4 | 132001022111121010312221 |
5 | 114301013420021414423 |
6 | 1144441412422551053 |
7 | 36544134453606564 |
oct | 3601122531046651 |
9 | 568402735284506 |
10 | 132021211123113 |
11 | 3907a976990824 |
12 | 12982718598489 |
13 | 58887153b1480 |
14 | 2485c09b1b4db |
15 | 103e2947c84e3 |
hex | 781295644da9 |
132021211123113 has 16 divisors (see below), whose sum is σ = 189578074518336. Its totient is φ = 81239898237120.
The previous prime is 132021211123093. The next prime is 132021211123129. The reversal of 132021211123113 is 311321112120231.
It is not a de Polignac number, because 132021211123113 - 233 = 132012621188521 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132021211133113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 80931918 + ... + 82547063.
It is an arithmetic number, because the mean of its divisors is an integer number (11848629657396).
Almost surely, 2132021211123113 is an apocalyptic number.
132021211123113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
132021211123113 is a deficient number, since it is larger than the sum of its proper divisors (57556863395223).
132021211123113 is a wasteful number, since it uses less digits than its factorization.
132021211123113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 163499704.
The product of its (nonzero) digits is 432, while the sum is 24.
Adding to 132021211123113 its reverse (311321112120231), we get a palindrome (443342323243344).
The spelling of 132021211123113 in words is "one hundred thirty-two trillion, twenty-one billion, two hundred eleven million, one hundred twenty-three thousand, one hundred thirteen".
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