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13202300320231 = 111200209120021
BaseRepresentation
bin1100000000011110011001…
…1010111011100111100111
31201202010110000020120220111
43000013212122323213213
53212301302340221411
644025015242313451
72531556211062361
oct300074632734747
951663400216814
1013202300320231
1142300783905a0
12159283b7b8887
13749c82732409
14338dcd819d31
1517d64ea42721
hexc01e66bb9e7

13202300320231 has 4 divisors (see below), whose sum is σ = 14402509440264. Its totient is φ = 12002091200200.

The previous prime is 13202300320217. The next prime is 13202300320303.

13202300320231 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13202300320231 - 211 = 13202300318183 is a prime.

It is a super-2 number, since 2×132023003202312 (a number of 27 digits) contains 22 as substring.

It is a Smith number, since the sum of its digits (22) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13202300320031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 600104560000 + ... + 600104560021.

It is an arithmetic number, because the mean of its divisors is an integer number (3600627360066).

Almost surely, 213202300320231 is an apocalyptic number.

13202300320231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13202300320231 is a deficient number, since it is larger than the sum of its proper divisors (1200209120033).

13202300320231 is a wasteful number, since it uses less digits than its factorization.

13202300320231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1200209120032.

The product of its (nonzero) digits is 1296, while the sum is 22.

It can be divided in two parts, 13202300 and 320231, that added together give a palindrome (13522531).

The spelling of 13202300320231 in words is "thirteen trillion, two hundred two billion, three hundred million, three hundred twenty thousand, two hundred thirty-one".

Divisors: 1 11 1200209120021 13202300320231