Base | Representation |
---|---|
bin | 1111101111010… |
… | …00001101001010 |
3 | 100012102110122222 |
4 | 13313220031022 |
5 | 232244214424 |
6 | 21033414042 |
7 | 3162115016 |
oct | 767501512 |
9 | 305373588 |
10 | 132023114 |
11 | 68583a13 |
12 | 3826a322 |
13 | 214765b2 |
14 | 13769546 |
15 | b8cce5e |
hex | 7de834a |
132023114 has 4 divisors (see below), whose sum is σ = 198034674. Its totient is φ = 66011556.
The previous prime is 132023113. The next prime is 132023117. The reversal of 132023114 is 411320231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 117007489 + 15015625 = 10817^2 + 3875^2 .
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 132023092 and 132023101.
It is not an unprimeable number, because it can be changed into a prime (132023113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33005777 + ... + 33005780.
Almost surely, 2132023114 is an apocalyptic number.
132023114 is a deficient number, since it is larger than the sum of its proper divisors (66011560).
132023114 is an equidigital number, since it uses as much as digits as its factorization.
132023114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66011559.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 132023114 is about 11490.1311567797. The cubic root of 132023114 is about 509.1940544852.
Adding to 132023114 its reverse (411320231), we get a palindrome (543343345).
The spelling of 132023114 in words is "one hundred thirty-two million, twenty-three thousand, one hundred fourteen".
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