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13202500114 = 26601250057
BaseRepresentation
bin11000100101110111…
…00010101000010010
31021002002211111101201
430102323202220102
5204014320000424
610022023221414
7645112253656
oct142273425022
937062744351
1013202500114
115665515821
1226855a786a
131325322c5b
148d35dca66
15524101d44
hex312ee2a12

13202500114 has 4 divisors (see below), whose sum is σ = 19803750174. Its totient is φ = 6601250056.

The previous prime is 13202500111. The next prime is 13202500117. The reversal of 13202500114 is 41100520231.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13202500111) and next prime (13202500117).

It can be written as a sum of positive squares in only one way, i.e., 11324577889 + 1877922225 = 106417^2 + 43335^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13202500091 and 13202500100.

It is not an unprimeable number, because it can be changed into a prime (13202500111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3300625027 + ... + 3300625030.

Almost surely, 213202500114 is an apocalyptic number.

13202500114 is a deficient number, since it is larger than the sum of its proper divisors (6601250060).

13202500114 is an equidigital number, since it uses as much as digits as its factorization.

13202500114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6601250059.

The product of its (nonzero) digits is 240, while the sum is 19.

The spelling of 13202500114 in words is "thirteen billion, two hundred two million, five hundred thousand, one hundred fourteen".

Divisors: 1 2 6601250057 13202500114