Base | Representation |
---|---|
bin | 11110000001001101111010… |
… | …100001111111110001010011 |
3 | 122022110110202010002120111012 |
4 | 132001031322201333301103 |
5 | 114301044303143202201 |
6 | 1144443250112041135 |
7 | 36544331644031420 |
oct | 3601157241776123 |
9 | 568413663076435 |
10 | 132025055444051 |
11 | 39081569a03a70 |
12 | 1298340bb331ab |
13 | 5888ba89960a3 |
14 | 2486092508d47 |
15 | 103e41c04b5bb |
hex | 78137a87fc53 |
132025055444051 has 128 divisors (see below), whose sum is σ = 179172029030400. Its totient is φ = 94155822858240.
The previous prime is 132025055443937. The next prime is 132025055444081. The reversal of 132025055444051 is 150444550520231.
It is a happy number.
It is a de Polignac number, because none of the positive numbers 2k-132025055444051 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132025055444081) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 2365291895 + ... + 2365347711.
It is an arithmetic number, because the mean of its divisors is an integer number (1399781476800).
Almost surely, 2132025055444051 is an apocalyptic number.
132025055444051 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
132025055444051 is a deficient number, since it is larger than the sum of its proper divisors (47146973586349).
132025055444051 is a wasteful number, since it uses less digits than its factorization.
132025055444051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56277.
The product of its (nonzero) digits is 480000, while the sum is 41.
The spelling of 132025055444051 in words is "one hundred thirty-two trillion, twenty-five billion, fifty-five million, four hundred forty-four thousand, fifty-one".
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