Base | Representation |
---|---|
bin | 10011001101101000000… |
… | …000111101101101111011 |
3 | 11200012220222110111021110 |
4 | 103031220000331231323 |
5 | 133112433302340011 |
6 | 2450312032011403 |
7 | 164250160124526 |
oct | 23155000755573 |
9 | 4605828414243 |
10 | 1320300043131 |
11 | 469a32a55043 |
12 | 193a71990b63 |
13 | 976719b6694 |
14 | 47c8d655bbd |
15 | 245261acba6 |
hex | 1336803db7b |
1320300043131 has 16 divisors (see below), whose sum is σ = 1793316672000. Its totient is φ = 863839398048.
The previous prime is 1320300043109. The next prime is 1320300043133. The reversal of 1320300043131 is 1313400030231.
It is not a de Polignac number, because 1320300043131 - 25 = 1320300043099 is a prime.
It is a super-2 number, since 2×13203000431312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1320300043098 and 1320300043107.
It is not an unprimeable number, because it can be changed into a prime (1320300043133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12155331 + ... + 12263468.
It is an arithmetic number, because the mean of its divisors is an integer number (112082292000).
Almost surely, 21320300043131 is an apocalyptic number.
1320300043131 is a deficient number, since it is larger than the sum of its proper divisors (473016628869).
1320300043131 is a wasteful number, since it uses less digits than its factorization.
1320300043131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24419138.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 1320300043131 its reverse (1313400030231), we get a palindrome (2633700073362).
The spelling of 1320300043131 in words is "one trillion, three hundred twenty billion, three hundred million, forty-three thousand, one hundred thirty-one".
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