Base | Representation |
---|---|
bin | 10011001101101000000… |
… | …101000111110110010011 |
3 | 11200012221001111212120111 |
4 | 103031220011013312103 |
5 | 133112434042230303 |
6 | 2450312111222151 |
7 | 164250202314553 |
oct | 23155005076623 |
9 | 4605831455514 |
10 | 1320301133203 |
11 | 469a3362a028 |
12 | 193a72217957 |
13 | 97671ca88b0 |
14 | 47c8d85b163 |
15 | 24526325b6d |
hex | 13368147d93 |
1320301133203 has 4 divisors (see below), whose sum is σ = 1421862758848. Its totient is φ = 1218739507560.
The previous prime is 1320301133201. The next prime is 1320301133269. The reversal of 1320301133203 is 3023311030231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1320301133203 - 21 = 1320301133201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1320301133201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50780812803 + ... + 50780812828.
It is an arithmetic number, because the mean of its divisors is an integer number (355465689712).
Almost surely, 21320301133203 is an apocalyptic number.
1320301133203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1320301133203 is a deficient number, since it is larger than the sum of its proper divisors (101561625645).
1320301133203 is a wasteful number, since it uses less digits than its factorization.
1320301133203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101561625644.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 1320301133203 its reverse (3023311030231), we get a palindrome (4343612163434).
The spelling of 1320301133203 in words is "one trillion, three hundred twenty billion, three hundred one million, one hundred thirty-three thousand, two hundred three".
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