Base | Representation |
---|---|
bin | 10011001101101000101… |
… | …100010100111100001001 |
3 | 11200012221202212000021221 |
4 | 103031220230110330021 |
5 | 133112444210113231 |
6 | 2450313115402041 |
7 | 164250355550422 |
oct | 23155054247411 |
9 | 4605852760257 |
10 | 1320311410441 |
11 | 469a39409511 |
12 | 193a75753321 |
13 | 976741666ba |
14 | 47c90d74649 |
15 | 245271a5d11 |
hex | 13368b14f09 |
1320311410441 has 8 divisors (see below), whose sum is σ = 1348452200160. Its totient is φ = 1292362708512.
The previous prime is 1320311410373. The next prime is 1320311410447. The reversal of 1320311410441 is 1440141130231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1320311410441 - 227 = 1320177192713 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1320311410447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48008055 + ... + 48035548.
It is an arithmetic number, because the mean of its divisors is an integer number (168556525020).
Almost surely, 21320311410441 is an apocalyptic number.
It is an amenable number.
1320311410441 is a deficient number, since it is larger than the sum of its proper divisors (28140789719).
1320311410441 is an equidigital number, since it uses as much as digits as its factorization.
1320311410441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96043895.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1320311410441 its reverse (1440141130231), we get a palindrome (2760452540672).
The spelling of 1320311410441 in words is "one trillion, three hundred twenty billion, three hundred eleven million, four hundred ten thousand, four hundred forty-one".
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