13203121301233 has 4 divisors (see below), whose sum is σ = 13265695336048. Its totient is φ = 13140547266420.

The previous prime is 13203121301231. The next prime is 13203121301273. The reversal of 13203121301233 is 33210312130231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13203121301233 - 2¹ = 13203121301231 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13203121301198 and 13203121301207.

It is not an unprimeable number, because it can be changed into a prime (13203121301231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31287017091 + ... + 31287017512.

It is an arithmetic number, because the mean of its divisors is an integer number (3316423834012).

Almost surely, 2^{13203121301233} is an apocalyptic number.

It is an amenable number.

13203121301233 is a deficient number, since it is larger than the sum of its proper divisors (62574034815).

13203121301233 is an equidigital number, since it uses as much as digits as its factorization.

13203121301233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62574034814.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 13203121301233 its reverse (33210312130231), we get a palindrome (46413433431464).

The spelling of 13203121301233 in words is "thirteen trillion, two hundred three billion, one hundred twenty-one million, three hundred one thousand, two hundred thirty-three".