Base | Representation |
---|---|
bin | 111101011110110101… |
… | …1100101111011001001 |
3 | 110121210111021000120021 |
4 | 1322331223211323021 |
5 | 4130400010341413 |
6 | 140353201500441 |
7 | 12352600606042 |
oct | 1727553457311 |
9 | 417714230507 |
10 | 132031340233 |
11 | 50aa3282111 |
12 | 21709041721 |
13 | c5b19a2bc0 |
14 | 65671a18c9 |
15 | 367b36718d |
hex | 1ebdae5ec9 |
132031340233 has 16 divisors (see below), whose sum is σ = 149884862400. Its totient is φ = 115295745600.
The previous prime is 132031340209. The next prime is 132031340251. The reversal of 132031340233 is 332043130231.
It is a cyclic number.
It is not a de Polignac number, because 132031340233 - 233 = 123441405641 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132031340198 and 132031340207.
It is not an unprimeable number, because it can be changed into a prime (132031340933) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 208123 + ... + 554416.
It is an arithmetic number, because the mean of its divisors is an integer number (9367803900).
Almost surely, 2132031340233 is an apocalyptic number.
132031340233 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
132031340233 is a deficient number, since it is larger than the sum of its proper divisors (17853522167).
132031340233 is a wasteful number, since it uses less digits than its factorization.
132031340233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 763272.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 132031340233 its reverse (332043130231), we get a palindrome (464074470464).
The spelling of 132031340233 in words is "one hundred thirty-two billion, thirty-one million, three hundred forty thousand, two hundred thirty-three".
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