Base | Representation |
---|---|
bin | 11110000001010011111101… |
… | …101010011011000000010111 |
3 | 122022111002111202120022120112 |
4 | 132001103331222123000113 |
5 | 114301201103402412401 |
6 | 1144450242410153235 |
7 | 36544651621403210 |
oct | 3601237552330027 |
9 | 568432452508515 |
10 | 132031550435351 |
11 | 390842a2190076 |
12 | 1298472312281b |
13 | 58896a24821c8 |
14 | 248650ad68407 |
15 | 103e69c35d3bb |
hex | 7814fda9b017 |
132031550435351 has 16 divisors (see below), whose sum is σ = 150929572242240. Its totient is φ = 113142623193600.
The previous prime is 132031550435261. The next prime is 132031550435363. The reversal of 132031550435351 is 153534055130231.
It is not a de Polignac number, because 132031550435351 - 210 = 132031550434327 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132031550435299 and 132031550435308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132031550435381) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1558753301 + ... + 1558838001.
It is an arithmetic number, because the mean of its divisors is an integer number (9433098265140).
Almost surely, 2132031550435351 is an apocalyptic number.
132031550435351 is a deficient number, since it is larger than the sum of its proper divisors (18898021806889).
132031550435351 is an equidigital number, since it uses as much as digits as its factorization.
132031550435351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 135754.
The product of its (nonzero) digits is 405000, while the sum is 41.
The spelling of 132031550435351 in words is "one hundred thirty-two trillion, thirty-one billion, five hundred fifty million, four hundred thirty-five thousand, three hundred fifty-one".
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