Base | Representation |
---|---|
bin | 1100000000100001111010… |
… | …0100010011111001001111 |
3 | 1201202012212122202021102020 |
4 | 3000020132210103321033 |
5 | 3212310220012144210 |
6 | 44025252532301223 |
7 | 2531621436565110 |
oct | 300103644237117 |
9 | 51665778667366 |
10 | 13203242303055 |
11 | 42305110881a2 |
12 | 1592a63171813 |
13 | 74a0a2937cbc |
14 | 33907c984207 |
15 | 17d6a75b3770 |
hex | c021e913e4f |
13203242303055 has 16 divisors (see below), whose sum is σ = 24143071640064. Its totient is φ = 6035767909920.
The previous prime is 13203242303021. The next prime is 13203242303137. The reversal of 13203242303055 is 55030324230231.
It is not a de Polignac number, because 13203242303055 - 29 = 13203242302543 is a prime.
It is a super-2 number, since 2×132032423030552 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62872582291 + ... + 62872582500.
It is an arithmetic number, because the mean of its divisors is an integer number (1508941977504).
Almost surely, 213203242303055 is an apocalyptic number.
13203242303055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13203242303055 is a deficient number, since it is larger than the sum of its proper divisors (10939829337009).
13203242303055 is a wasteful number, since it uses less digits than its factorization.
13203242303055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 125745164806.
The product of its (nonzero) digits is 64800, while the sum is 33.
Adding to 13203242303055 its reverse (55030324230231), we get a palindrome (68233566533286).
The spelling of 13203242303055 in words is "thirteen trillion, two hundred three billion, two hundred forty-two million, three hundred three thousand, fifty-five".
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