132032511240115 has 4 divisors (see below), whose sum is σ = 158439013488144. Its totient is φ = 105626008992088.

The previous prime is 132032511240101. The next prime is 132032511240137. The reversal of 132032511240115 is 511042115230231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132032511240115 - 2¹³ = 132032511231923 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13203251124007 + ... + 13203251124016.

It is an arithmetic number, because the mean of its divisors is an integer number (39609753372036).

Almost surely, 2^{132032511240115} is an apocalyptic number.

132032511240115 is a deficient number, since it is larger than the sum of its proper divisors (26406502248029).

132032511240115 is an equidigital number, since it uses as much as digits as its factorization.

132032511240115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26406502248028.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 132032511240115 its reverse (511042115230231), we get a palindrome (643074626470346).

The spelling of 132032511240115 in words is "one hundred thirty-two trillion, thirty-two billion, five hundred eleven million, two hundred forty thousand, one hundred fifteen".